Transforms and its Applications: UNIT 1: Laplace Transforms

Transforms of Derivatives and Integrals

Laplace Transforms

Laplace Transforms: Example Important Solved Problems with formula, steps, derivation and answer based on Transforms of Derivatives and Integrals

TRANSFORMS OF DERIVATIVES AND INTEGRALS

 

Result : Prove that L[f '' (t)] = s L[ f(t)] ‒ f(0)

Proof:

We know that,


 = ‒f(0) + sL[f(t)] = s L [ft] ‒ f(0)

 

Result : Prove that L [f '' (t)] = s2 L [f(t)] − sf(0) – f '(0)

Proof: We know that,


= [0 ‒ f '(0)] + s 0ʃe‒st f ' (t) dt

= ‒f ' (0) + s L [f ' (t)]

= ‒f '(0) + s[sL [f(t)] ‒ [f(0)] by result (15)

 L [f ''(t)] = s2L[f(t)] − s f (0) ‒ f'(0)

Note: (15)

 L[F(n)(t)] = sn L[f(t)] ‒ sn‒1f(0) ‒ sn‒2 f '(0) ‒ ... ‒f(n‒1)(0)


Transforms of integrals

 

Result : If L[f(t)] = F(s), then L [ 0ʃt f(u) du ] = 1/s L[f(t)]


Proof:

Given: L [f(t)] = F(s)

Let ϕ(t) = 0ʃt f(u) du,

 then ϕ'(t) = f(t) and ϕ(0) = 0          ….(1)

L [ϕ'(t)] = sL [ϕ(t)] ‒ ϕ(t) = sL[ϕ(t)]

 L [ϕ(t)] = 1/s L [ϕ'(t)]


 

Transforms and its Applications: UNIT 1: Laplace Transforms : Tag: Engineering mathematics, Maths : Laplace Transforms - Transforms of Derivatives and Integrals


Transforms and its Applications: UNIT 1: Laplace Transforms



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