Explanation, Formula, Equation, Example and Solved Problems - Partial derivatives: Problems under type-4
PROBLEMS UNDER TYPE 4
Let u= f(r,s,t). r, s and t are functions
of x, y, z.Then

Example
34. If u = f(x‒y, yz, z‒x), then
prove that ∂u/∂x + ∂u/∂y + ∂u/∂z =0.
Solution:
Let r=x‒y, s=y‒z, tz‒x.
:. u = f(r,s,t)

Example
35. If u = f(2x‒3y, 3y‒4z, 4z‒2x),
then prove that
.
Solution:
Let r = 2x‒3y, s = 3y‒4z, t = 4z ‒ 2x
u = f(r,s,t)

Example
36. If u = f(x/y, y/z, z/x), then
prove that x.∂u/∂x + y.∂u/∂y + z.∂u/∂z
= 0.
Solution:
Let r =x/y, s =y/z, t =z/x.
:. u = f(r,s,t)

Example
37. If u = u( y‒x / xy, z‒x / xz),
then prove that
.
Solution:

Example
38. If u = f(x, y), where x = r cos 0, y = r sin 0, then P.T 
Solution.
Given x =
r cos 0, y = r sin 0

Example
39. If Z = f (u,v), where u = lx + my,
v = ly‒mx then prove that
.
Solution:
Given u = lx + my, v = ly ‒ mx

Example
40. Prove that
, u =
excosy, v = exsiny and that f is a function of u and v and also of x and y.
Solution:
Given u = excosy, v
= exsin y

Hence the proof
Example
41. If f = f(u, v), where u = x2‒y2 and v = 2xy, then show that
.
Solution:
Given u = x2 ‒ y2;
v = 2xy

Example
42. Transform the equation ∂2z/∂x2
+ ∂2z/∂y2 = 0
into polar co ordinates.
Solution:
Polar co‒ordinate is x = r cos 0, y = r sine
x2
+ y2 = r2
r
=
√[x2 + y2]
y/x = tanθ
θ= tan‒1x/y

EXERCISE
46. Find du/dx
when u = sin(x2 + y2),
where x2 + 4y2 = 9.
Ans:
3xcos(x2+y2) / 2
47. Find du/dx
when u = tan‒1(y/x), where
x2 + y2 = a2.
Ans:
‒1/y
48. Find du/dt
if u=x/y where x = et, y = log t.
Ans:
dz/dt = et/logt [ 1‒ 1/tlogt
]
49. If z = x2 + y2,
where x = t3, y = 1 + t2, find dz/dt.
Ans:
= dz/dt = 6t6 + 4t + 4t3
50. If ax2 + 2hxy + by2 = 1,
then prove that d2y/dx2
= h2‒ab / (hx+by)3
51. Using partial
Derivative find dy/dx for (sec x)y = (cot y)x.
Ans. [
log
coty ‒ y tan x ] / [log secx + x secy cosec y]
52. Using partial
Derivative find dy/dx for (cos x)y = (sin x)y.
Ans.
[ y
tan
x + log sin y ] / [ log cos x ‒ x coty ]
53. If ƒ (cx ‒ az, cy ‒
bz) = 0, where z is a function of x and y, prove that a.∂z/∂x + b. ∂z/∂y
= c.
54. If ƒ is a function
of u, v, w where u = √(yz), v = √(zx), w= √(xy) show that 
55. If u = u(x, y) and x = er cos θ,
y = er sin θ, show that 
56. If z = f(u, v), where u = coshx cosy and v = sin hx sin y, then prove that 
57. Transform the
equation
, by changing the independent variables using u = 2x
+ y and v = 3x + y.
Ans:
∂2z/∂u∂u = 0
58. Using partial
differentiation, prove d2y/dx2
= b2‒ac / (ay+b)3
when ay2+2by + c = x2.
59. If u = f(r,s),
r=x+at, s= y + bt, then show
that ∂u/∂t = a [∂u/∂x] + b [∂u/∂x]
60. If z = f(x,
y) where, x = Xcosa ‒ Ysina and y = Xsina + Ycosa show
.
61. Transform the
equation
= 0 by changing the independent variables using u = x ‒
y and v = x + y.
Applied Calculus: UNIT II: Functions of Several Variables : Tag: Applied Calculus : - Partial derivatives: Problems under type-4
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