Construction of four variable karnaugh map for a given Pairs
CONSTRUCTION OF FOUR VARIABLE
K‒MAP FOR A GIVEN TRUTH TABLE
Let
us consider a Table 2.17. In this, the input variable A,B,C & D and output
variable Y forms a Truth Table.

Step 1:
Look for output 1s in the Truth table (Table 2.17)
Step 2:
Write the minterms.
The
minterms are 
Step 3:
Now enter 1s for the product
and 0s in the remaining cells, the complete
Karnaugh map looks like as shown in Fig.2.17A.

In
another way the minterms
can be represented by function F(A,B,C,D) = Σm (1,6,7,10,14).
Here
Σ and m represents SOP and minterms respectively and 1,6,7,10,14 are cell order
values. The construction of Karnaugh map is as shown in Fig.2.17(B). Fig.
2.17(A) and 2.17(B) represents same SOP minterms for the Table 2.17.

Step 1:
Look for output 0s in the Truth table (Table 2.17)
Step 2:
Write the Maxterms.
The
Maxterms are

Step 3:
Now enter 0s for the sum

and
1s in the remaining cells, the complete Karnaugh map for POS looks like as
shown in Fig.2.18(A)


Fig.
2.18(A) and 2.18(B) represents same POS Maxterms for the Table 2.17
In
another way the Maxterms

can
be represented by function F(A,B,C,D) C,D) = Π M (0,2,3,4,5, 8,9,11,12,13,15).
Here
Π and M represents POS and Maxterms respectively and 0,2,3,4,5,8,9,11,12,13,15
are cell order values. The construction of Karnaugh map is as shown in
Fig.2.18(B).
Note:
Σm (or) Σ both represents SOP
ΠM
(or) Π both represents POS
Applied Physics CSIE II: UNIT II: Logic Gates : Tag: Applied Physics : - Construction of four variable K map for a given Pairs
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