Applied Physics I: Chapter 9: Applied Optics - Fiber Optics
Fiber Optics: Important Solved Problems
Anna University Solved Problems, Additional Solved Problems, Assignment Problems - Questions with solved Solution and Answer - Applied Physics I: Chapter 9: Applied Optics - Fiber Optics
ANNA
UNIVERSITY SOLVED PROBLEMS
1. A silica optical
fiber has a core refractive index of 1.50 and a cladding refractive index of
1.47. Calculate the critical angle at the core‒cladding interface.
Given
Data
n1 = 1.50;
n2 = 1.47
Formula: Critical
angle θc = sin‒1 ( n2
/ n1)
θc = sin‒1 ( 1.47 / 1.50
)
θc
= 78.52
(or)
θc = 78°.31'
The Critical angle at the core‒cladding interface 78°.31'
2. A signal of 100 mW
is injected into a fibre. The outcoming signal from the other end is 40 mW.
Find the loss in dB?
Solution
Given
Data
Power
input (Pin) = 100mW
Power
output (Pout) = 40mW
Formula:
Power loss (PL) = 10 log(Pout/Pin)
dB
PL = 10 log(Pout/Pin)
dB
PL = 10 log(40×10‒3/100×10‒3)
dB
PL = 10 log (0.4) dB
PL = ‒ 3.979 dB
Here,
the negative sign indicates the loss of power, with respect to distance travelled
by the signal through the fibre.
The power loss PL = ‒ 3.979 dB
ASSIGNMENT
PROBLEMS
1.
Two layers of glass are placed one over the other. Find the critical angle for
which the total internal reflection takes place if the light travels from n1
= 1.45 to n2=1.40. (Ans: ϕc=74.9°)
2.
A fibre has ncore = 1.44 and ncladding = 1.40. Find
acceptance angle. (Acceptance angle = 19.7°)
3.
Compute the acceptance angle of n1 = 1.55, n2 = 1.50, no
= 1.(Acceptance Angle = 23°)
4.
A silica optical fibre has a core refractive index of 1.50 and of cladding
refractive index 1.47. Determine ϕc and im. (Ans: ϕc =78.5°; im =
17.5°)
Applied Physics I: Chapter 9: Applied Optics - Fiber Optics : Tag: Applied Physics : - Fiber Optics: Important Solved Problems
Applied Physics I: Chapter 9: Applied Optics - Fiber Optics
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