The solution of one‒dimensional potential box can be extended for a three dimensional potential box. In a three dimensional potential box, the particle (electron) can move in any direction in space.
PARTICLE IN A THREE
DIMENSIONAL (3D) POTENTIAL BOX
The
solution of one‒dimensional potential box can be extended for a three
dimensional potential box. In a three dimensional potential box, the particle
(electron) can move in any direction in space. Therefore instead of one quantum
number 'n', we have to use three
quantum number nx, ny, and nz corresponding the three co‒ordinate axis (ie) x, y
and z respectively.
Let
us consider a particle enclosed in a 3‒dimensional potential box of length a, b
and c along x, y and z axis respectively as shown in Fig. 7.8.

Since
the particle inside the 3D box has elastic collisions with the walls, the
potential energy of the electron inside the box is constant and can be taken as
zero for simplicity.
∴ We can say that
outside the box and on the wall of the box, the potential energy is ∞.
∴
The boundary conditions are
Boundary
conditions
1.
V (x, y, z) = 0 when 0<x<a
V
(x, y, z) = 0 when 0<x<b
V
(x, y, z) = 0 when 0 < x <c
Inference:
Within this boundary the particle exist and we need to find the energy values
and wave function ...(1)
2.
V (x, y, z) = ∞ when 0≥x≥a
V
(x, y, z) = ∞ when 0≥x≥b
V
(x, y, z) = ∞ when 0≥ x ≥ c
Inference:
In this area the particle does not exist and therefore the wave function = 0 ...(2)

To
find the wavefunction of the particle within the boundary conditions (1).
Let
us consider the 3‒dimensional schrodinger time independent wave equation,
i.e.,

……….....(3)
Since
V=0 [For a free particle], we can write eqn (3) as

…………..
(4)
Equation
(4) is a partial differential equation, in which ᴪ is a function of three
variables, x, y and z.
∴ We can solve this
using method of separation of variables.
∴ The solution for eqn
(4) can be written as
ᴪ(x, y, z) = ᴪx ᴪy ᴪz
Which
means ᴪ is a function of x, y and z and is equal to product of 3 functions
i.e., ᴪx, ᴪy, and ᴪz.
Where
ᴪx
is a function of x only
ᴪy
is a function of y only
ᴪz
is a function of z only
∴ We can write the
solution for equation (4) as ᴪ= ᴪx
ᴪy ᴪz
………(5)
Differentiating
eqn (5), Partially with respect to 'x', twice, we get

Similarly
differentiating eqn (5) partially with respect to 'y', twice, we get

Similarly
differentiating eqn (5) partially with respect to 'z', twice, we get

Substituting
equations (5), (6), (7) and (8) in eqn (4) we get

In
equation (10), L.H.S. is independent of each other and is equal to a constant
in R.H.S. ∴
we can equate each term of L.H.S. to each constant in R.H.S.
∴ We can write

Equations
(12), (13) and (14) represents the differential equations in x, y and z co‒ordinates.
The solution for equation (12) can be written as
ᴪx = Ax sin kxx + Bx cos kxx …....(15)
where
Ax and Bx are arbitrary constants, which can be found by
applying boundary conditions.
(i) When x=0; x=0
∴ Equation (15) becomes
0 = 0 + Bx
∴ Bx = 0 ……...(16)
(ii) When x=a; X=0
∴ Equation (15) becomes
0=Ax sin kxa
Here
Ax ≠ 0
[Because, if Аx=0, then ᴪx
becomes zero, which implies that the particle is not there, and is meaningless]
∴ sin kxa = 0
We
know sin nxπ = 0
Comparing
the above two equations we can write kxa = nxπ
(or) kx = nxπ / a …………..(17)
Substituting
equations (16) & (17) in eqn (15) we get

……....(18)
Equation
(18) represents the un‒normalized wave function.
Eqn
(18) can be normalized by integrating it within the limits i.e., boundary
conditions 0 to a,
We
can write 0∫a |ᴪx|2 dx = 1

Substituting
eqn (19) in (18) we get

Similarly
by solving equation (13) and equation (14) with the boundary conditions 0 to b
and 0 to c respectively, we can write

The
complete wave function, for equation (4) can be written as
ᴪ(x, y, z) = ᴪx ᴪy ᴪz
Substituting
equations (20), (21) and (22) in the above equation, we get

Equation
(23) represents the eigen function for an electron in a 3‒dimensional potential
box.
From
equation (11) we can write

Substituting
these values in eqn (24), we get

Equation
(25) represents the energy eigen values of an electron in a 3‒dimensional
potential box (cuboid).
For
a cubical box, a = b = c,
∴ We can write equation
(25) as

The
corresponding normalized wave function of an electron in a cubical box can be
obtained from equation (23), as

From
equations (26) and (27) we can note that, several combinations of the three
quantum numbers (nx, ny and nz) leads to
different energy eigen values and eigen functions.
If
a state has quantum numbers nx = 1; ny = 1; nz=2
Then,
nx2+ny2+nz2=
6
Similarly for nx=1; ny=2; nz=1 combination and nx=2 , ny=1 , nz=1 combination we have nx2+ny2+nz2= 6
E112‒E121
= E211 = 6h2 / 8ma2 ………………(28)
The
corresponding wave functions can be written as

The
energy values for various set of quantum number combination is as shown in Fig.
7.9, from which we can conclude that the energy values are discrete.

Applied Physics I: Chapter 7: Quantum Mechanics : Tag: Applied Physics : - Particle in a three dimensional (3d) Potential box
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