Applied Physics I: Chapter 6: Oscillations and Waves - Electromagnetic Waves

Electromagnetic Waves: Important Solved Problems

Anna University Solved Problems, Additional Solved Problems, Assignment Problems - Questions with solved Solution and Answer - Applied Physics I: Chapter 6: Oscillations and Waves - Electromagnetic Waves

IMPORTANT SOLVED PROBLEMS

 

1. The electric field vector of a plane electromagnetic wave oscillates sinusoidal at a frequency 7.5×1010 Hz. Find the wave length of this wave.

Solution

Electric field vector frequency f = 7.5×1010 Hz

Given data

Formula:

 v = c/ λ      (or)      λ=c/v

λ = 3×108 / 7.5×1010

λ = 0.4 / 100

λ = 4 / 1000

 λ = 4×10‒3m

Wave length λ = 4 × 10−3 m

 

2. Electric field of plane electromagnetic wave is 450 NC‒1. Find the magnetic field in wave.

Solution

Given data

Electric field vector E = 450 NC‒1

Formula:

Magnetic field B = E/c

B = 450 / 3×108

B = 150 / 108

B =1.5×10‒6 T

Magnetic field B = 1.5 × 10−6 Tesla

 

3. Amplitude of electric field in plane electromagnetic wave is 200NC‒1 and its frequency is 7×107 Hz. Determine the magnetic field amplitude and magnitude of wave vector.

Solution

Amplitude of electric field E = 200NC‒1

Frequency v = 7×107 Hz

Given data

Amplitude of magnetic field B = E/c

B = 200 / 3×108

B = 66.6 / 108

B = 6.6 × 10‒7T

Magnitude of wave vector k = ω/c = 2πν / c

k = [ 2×3.14×7×107 ] / [ 3×108 ]

k = 43.96×107 / 3×108

k= 14.65 / 10

k=1.465

(i) Magnetic field B = 6.6. × 10‒7 Telsa

(ii) Magnetude of wave vector k = 1.465

 

4. The magnetic field strength of an electromagnetic field is 5×10+6 T. Calculate the electric field strength if the wave is traveling in a medium in which the speed of the wave is 0.75c.

Solution

Given data

Magnetic field strength B = 5×10+6 T

Speed of the wave v=0.75 c

Electric field strength E=?

Formula:

Electric field strength E=vB

E=vB

E=0.75×3×108×5×10‒6

E=11.25×102

E=1125 NC‒1.

Electric field strength E = 1125 NC‒1

 

5. Calculate the speed of the electromagnetic wave in a medium if the amplitude of electric and magnetic fields are 6 x 104 NC‒1 and 4× 10‒4 T, respectively.

Solution

Given data

Amplitude of electric fields E0 = 6 × 104 N C‒1

Amplitude of magnetic fields B0 = 4 × 10‒4 T

Speed of the electromagnetic wave in a medium v = ?

Formula:

Speed of EM wave in medium

v = E0 / B0

v = 6×104 / 4×10‒4

v = 1.5 × 108 ms‒1

Speed of EM wave in medium v = 1.5 × 108 ms‒1

 

ASSIGNMENT PROBLEMS

 

1. The electric field vector of a plane electromagnetic wave oscillates sinusoidal at a frequency 6.80 × 1010 Hz. Find the wave length of this wave. (Ans 4.4 × 10‒9 m)

 

2. Electric field of plane electromagnetic wave is 500 NC‒1 and the velocity of wave is 2.5 × 108 meter per second. Find the magnetic field in wave. (Ans 2 × 10‒4 T)

 

Applied Physics I: Chapter 6: Oscillations and Waves - Electromagnetic Waves : Tag: Applied Physics : - Electromagnetic Waves: Important Solved Problems


Applied Physics I: Chapter 6: Oscillations and Waves - Electromagnetic Waves



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