Fourier Series: Example Important Solved Problems with formula, steps, derivation, answer and Exercise Problems based on Solutions of One Dimensional Wave Equation - Vibrating String with Initial Velocity and Initial Displacement Given.
ONE
DIMENSIONAL WAVE EQUATION: VIBRATING STRING WITH INITIAL VELOCITY AND INITIAL
DISPLACEMENT GIVEN
The
initial and boundary conditions are
(i)
y (0, t) = 0
(ii)
y (l, t) = 0
(iii)
( ∂y/∂t )(x, 0) = g(x)
iv)
y(x, 0) = f(x)
The
suitable solution is a
y(x, t) = (C1 cos px + C2
sin px) (C3 cos p at + C4 sin p at)
…………(1)
Apply
condition (i) we get C1 = 0
Apply
condition (ii), we get p = nπ/l
The
most general form is

Substitute,
Cn, Dn values in (2), we get the general solution.
Example 23: Solve the problem of the vibrating
string for the following boundary conditions: (i) y (0, t) = 0, (ii) y (l, t) = 0
(iii) ∂y/∂t (x, 0) = x(x−1), 0<x<l (iv) y (x, 0) = 
Solution:
The wave equation is 
From
the given problem, we get the following boundary and initial conditions
(i)
y (0, t) = 0 for all t> 0
(ii)
y (l, t) = 0 for all t > 0
(iii)
( ∂y/∂t )(x, 0) = g(x) =
x(x‒l), 0<x<l
iv)
y(x, 0) = f(x) = 
Now,
the suitable solution which satisfies our boundary conditions is given by
y (x, t) = (c1 cos px + c2
sin px) (c3 cos pat + c4 sin pat) …….(1)
Applying
condition (i) in equation (1), we get
y (0, t) = (c1+0) (c3 cos p at + c4
sin p at) = 0
Here,
c3 cos pat + c4 sin pat ≠ 0 [. It is defined for all t]
Therefore,
we get c1 = 0
Substitute,
c1 0 in equation (1), we get
y (x, t) = c2 sin px (c3
cos pat + c4 sin pat)
Applying
condition (ii) in (2), we get
y (l,
t) = c2 sin pl (c3 cos pat + c4 sin pat) = 0
Here,
c3 cos pat + c4 sin pat ≠ 0 ['. it is defined for all t]
Therefore,
either c2 = 0 or sin pl =
0
Suppose,
we take c2 = 0 and already we have
c1 = 0 then we get a trivial solution.
Therefore,
we consider c2 ≠ 0 and
sin
pl = 0
pl =
nπ
[sin nπ= 0]
p = nπ / l
[n being an integer]




1.
A string is stretched between two fixed points at a distance of π cm and the
points of the string are given initial velocities v, where
ν= x, in 0 < x < π/2
= π‒x, in π/2 <x<π after displacing it
to the position
y = x(π‒x) at t=0. Find the displacement of
the string at any time.

2.
Find the displacement of a tightly stretched string of length 7 cm vibrating
between fixed end points, if initial displacement is 10 sin (3πx/7) and initial
velocity is 15 sin(9πx/l).

Transforms and its Applications: UNIT 3: Fourier Series : Tag: Engineering mathematics, Maths : - Fourier Series: Solutions of One Dimensional Wave Equation - Vibrating String with Initial Velocity and Initial Displacement Given
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